Question #203524

a 50m high object was seen via a telescope 100m from a 3.5mm focal length converging lens. Determine the image distance, magnification, and object height


1
Expert's answer
2021-06-07T09:35:44-0400

Gives

Objectdistance(o)=Object distance (o)= 100m

Focal length (d)=3.5mm

We know that



1o+1I=1f\frac{1}{o}+\frac{1}{I}=\frac{1}{f}

Put value

1I=13.5×1031100\frac{1}{I}=\frac{1}{3.5\times10^{-3}}-\frac{1}{100}

Object distance dI=3.5×103md_I=3.5\times10^{-3}m

Magnificent

m=Iom=\frac{I}{o}

Put value

m=3.5×103100m=\frac{3.5\times10^{-3}}{100}

m=3.5×105m=3.5\times10^{-5}

Object hight

Io=hh\frac{I}{o}=\frac{h}{h'}

h=Io×hh'=\frac{I}{o}\times h

Put value

h=50100×3.5×103h'=\frac{50}{100}\times3.5\times10^{-3}

h=1.75×103mh'=1.75\times10^{-3}m

h=1.75mmh'=1.75mm


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