Gives
Objectdistance(o)= 100m
Focal length (d)=3.5mm
We know that
o1+I1=f1
Put value
I1=3.5×10−31−1001
Object distance dI=3.5×10−3m
Magnificent
m=oI
Put value
m=1003.5×10−3
m=3.5×10−5
Object hight
oI=h′h
h′=oI×h
Put value
h′=10050×3.5×10−3
h′=1.75×10−3m
h′=1.75mm
Comments