Answer to Question #201761 in Electric Circuits for Nipesh Chaudhary

Question

There are too conductors A & B of the same material.

having length l & 2l: & having radii r & r/2 respectively. what is the ratio of their resistances?

Answer 1

Gives

$l_1=L$

$l_2=2L$

$r_1=r$

$r_2=\frac{r}{2}$

We know that resistance

$R=\frac{\rho l}{A}$

Now

$\frac{R_1}{R_2}=\frac{l_1}{l_2}\times (\frac{r_2}{r_1})^2$

Put Value

$\frac{R_1}{R_2}=\frac{L}{2L}\times (\frac{\frac{r}{2}}{r})^2$

$\frac{R_1}{R_2}=\frac{1}{8}$