Question

A 10 W resistor ,15.9 mH inductor and 159 micro farad capacitor are connected in parallel to a 200V, 50 Hz source. Calculate the supply current.

Answer 1

Gives 

Resistance (R)=10 ohm

Power supply (V)=200V

Frequency (n)=50Hz

Inductor(L)=15.9mH

Capacitor (C)=159microferad

$I=\frac{V}{Z}$

Z=impedence

$Z=\sqrt{R^2+({X_L-X_C})^2}$

X_L=wL=$2\pi f$ $X_L=2\times3.14\times50\times15.9\times10^{-3}=4.9926 \Omega$

$$X_C=\frac{1}{2\times3.14\times50\times159\times10^{-6}}=20.03\Omega$$

put Value

$Z=\sqrt{10^2+15.03^2}=18.05\Omega$

$I=\frac{200}{18.05}=11.08A$