A battery powered torch uses a 9 V battery and dissipates 0.25 W of electrical power in the bulb.
If the torch is used for 1.0 hours then how much charge has passed through the bulb? (to 2 s.f and in C)
P=0.25 WV=9 Vt=1.0 hour=1×60×60=3600 secI=PV=0.259=0.02777 AQ=It=0.02777×3600=100 CP = 0.25 \;W \\ V = 9 \;V \\ t = 1.0 \;hour = 1 \times 60 \times 60 = 3600 \;sec \\ I = \frac{P}{V} \\ = \frac{0.25}{9}=0.02777 \;A \\ Q = It \\ = 0.02777 \times 3600 = 100 \;CP=0.25WV=9Vt=1.0hour=1×60×60=3600secI=VP=90.25=0.02777AQ=It=0.02777×3600=100C
Answer: 100 C
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