A dc electric motor consumes 36000000 Joules when connected to a 0.25 kV supply for 60 minutes. Find the current taken from the supply?
Answer by choosing the closest answer of this question from the following choices.
a. 40 W
b. 30 A
c. 40 A
d. 10000 W
Gives
Energy (E)=36000000J
Supply voltage (V)=0.25KV
time =60min =3600sec
We know that
"P=\\frac{E}{t}\\rightarrow(1)"
"P=IV\\rightarrow(2)"
equation (1)and(2) equal
"\\frac{E}{t}=IV"
"I=\\frac{E}{tV}"
"I=\\frac{36000000}{3600\\times250}" =40A
Option (c) is correct option
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