Question

Equivalent capacitance of parallel combination is different from that of series combination.justify

Answer 1

Assume two capacitor is capacitance

$C_1,C_2$

Series combination

$Q=Q_1+Q_2$

$\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}$

$C=\frac{{C_1}{C_2}}{C_1+C_2}$

When n capacitor connect in series combination $C_1,C_2,C_3........C_n$

Then

$C_{net}=\frac{C}{n}$

Parallel combination

$V=V_1+V_2$

$C=C_1+C_2$

When n capacitor connect in series combination $C_1,C_2,C_3.........C_n$

Then

$C_{net}=nC$