Question

a 12 resistor and a 15 resistor are connected in series Across 9.0 V potential difference what is the current in the circuit

Answer 1

Gives

$R_1=12 \Omega$

R₂=15$\Omega$

v =9.0V

Series combination

$R=R_1+R_2$

$R=12+15\Omega$

We know that

$V=IR$

$I=\frac{V}{R}$

Put value

$I=\frac{9.0}{27}=0.33A$