a 12 resistor and a 15 resistor are connected in series Across 9.0 V potential difference what is the current in the circuit
Gives
"R_1=12\n\\Omega"
R2=15"\\Omega"
v =9.0V
Series combination
"R=R_1+R_2"
"R=12+15\\Omega"
We know that
"V=IR"
"I=\\frac{V}{R}"
Put value
"I=\\frac{9.0}{27}=0.33A"
Comments
Leave a comment