Answer to Question #196033 in Electric Circuits for Kenma

Question #196033

An oxygen-16 ion with a mass of 2.66 × 10−26 kg travels at 7.33 × 106 m/s perpendicular to a 7.23 – T magnetic field, which makes it move in a circular arc with a 0.652-m radius. What positive charge (in x10-19) is on the ion? 


answer to 2 decimal places


1
Expert's answer
2021-05-26T12:55:33-0400

F=ma=qvB and a=v2rF=ma=qvB \space and \space a =\frac{v^2}{r}

qvB=mv2rqvB=\frac{mv^2}{r}

q=mvrB=(2.66×1026×7.33×106)(0.652×7.23)=4.14×1020Cq=\frac{mv}{rB}=\frac{(2.66\times 10^{-26}\times 7.33\times 10^6)}{(0.652\times 7.23)}=4.14\times10^{-20}C

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