Answer to Question #196025 in Electric Circuits for Asahi

Question #196025

Your car’s 59-W headlight and 25-kW starter are ordinarily connected in parallel in a 16-V system. What power would one headlight and the starter consume if connected in series to a 16-V battery? (Neglect any other resistance in the circuit and any change in resistance in the two devices.)


answer to 2 decimal places.


1
Expert's answer
2021-05-21T10:42:54-0400

Power consumed by headlight, P1=59 WP_1=59\space W

As it is connected parallel with 16V system

Therefore potential difference across headlight and starter will be same

V=16 VV=16\space V

Resistance offered by headlight, R1=V2P1=4.33 ΩR_1=\dfrac{V^2}{P_1}=4.33\space \Omega

Power consumed by starter, P2=25×103 WP_2=25\times10^3\space W

Resistance offered by headlight, R2=V2P2=0.01024 ΩR_2=\dfrac{V^2}{P_2}=0.01024\space \Omega

Total resistance offered when both the devices are connected in series

Rtotal=R1+R2=4.34024 ΩR_{total}=R_1+R_2=4.34024\space \Omega

Current in the circuit, Itotal=16Rtotal=3.686 AI_{total}=\dfrac{16}{R_{total}}=3.686\space A

Power consumed by headlight, P1=Itotal2R1=58.84 WP_1'=I_{total}^2R_1=58.84\space W

Power consumed by starter, P2=Itotal2R2=0.139 WP_2'=I^2_{total}R_2=0.139\space W

Total power consumed in series, Ptotal=P1+P2=58.97 WP_{total}=P_1'+P_2'=58.97\space W


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment