Gives capacitance (C)=25μF\mu FμF
Potential difference (V)=1000 V
We know that
Q=CV
Q=25×10−6×1000CQ=25\times10^{-6}\times1000 CQ=25×10−6×1000C
Q=25×10−3CQ=25\times10^{-3}CQ=25×10−3C
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