Question #194260
A 25 μF capacitor is connected to a source of potential difference of 1000 V. What is the resulting charge on the capacitor?
1
Expert's answer
2021-05-17T18:46:21-0400

Gives capacitance (C)=25μF\mu F

Potential difference (V)=1000 V


We know that

Q=CV

Q=25×106×1000CQ=25\times10^{-6}\times1000 C

Q=25×103CQ=25\times10^{-3}C


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