Equivalent Capacitance, Ceq=(C11+C21+C31+C41+C51)−1
Ceq=51=0.20 μF
Voltage across c3, V3=5 V
Therefore charge stored in c3, q3=c3×V3=5×10−6 C
Since, the capacitors are connected in series therefore charge stored in each capacitor is same and so is the voltage as all capacitors have same capacitance i.e q1=q2=q3=q4=q5=5×10−6 C
and
V1=V2=V3=V4=V5=5 V
Total voltage, V=25 V
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