Question #194074

Determine the charge in each capacitor and the voltage across each capacitor.

Given: V3= 5V

C1=1uF

C2= 1uF

C3= 1uF

C4= 1uF

C5= 1uF


1
Expert's answer
2021-05-18T17:30:18-0400

Equivalent Capacitance, Ceq=(1C1+1C2+1C3+1C4+1C5)1C_{eq}=\bigg(\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}+\dfrac{1}{C_4}+\dfrac{1}{C_5}\bigg)^{-1}

Ceq=15=0.20 μFC_{eq}=\dfrac{1}{5}=0.20\space\mu F

Voltage across c3, V3=5 Vc_3,\space V_3=5\space V

Therefore charge stored in c3, q3=c3×V3=5×106 Cc_3,\space q_3=c_3\times V_3=5\times10^{-6}\space C

Since, the capacitors are connected in series therefore charge stored in each capacitor is same and so is the voltage as all capacitors have same capacitance i.e q1=q2=q3=q4=q5=5×106 Cq_1=q_2=q_3=q_4=q_5=5\times10^{-6}\space C

and

V1=V2=V3=V4=V5=5 VV_1=V_2=V_3=V_4=V_5=5\space V


Total voltage, V=25 VV=25\space V


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