Question #193046

A coil of wire is made of 520 turns and has an area of 0.30 m^2. It is placed in a uniform magnetic field of magnitude 0.40 T. This magnetic field flips its orientation from 0.40 T in the +y-direction to 0.40 T in the −y-direction in 2.0 s. How much power is generated in the coil if it has a resistance of 1200 Ω ?


1
Expert's answer
2021-05-16T17:53:36-0400

Number of turns, n=520n=520

Area of of cross section, A=0.30 m2A=0.30\space m^2

Emf induced, ϵ=nΔΦΔt=nBA(BA)2|\epsilon|=n\dfrac{|\Delta\Phi|}{|\Delta t|}=n\dfrac{|BA-(-BA)|}{2}

ϵ=520×2BA2=520×0.40=208 V|\epsilon|=520\times\dfrac{|2BA|}{2}=520\times0.40=208\space V


Resistance, R=1200 ΩR=1200\space\Omega

Power generated, P=V2R=(208)21200=36.05 WP=\dfrac{V^2}{R}=\dfrac{(208)^2}{1200}=36.05\space W


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