The value Io of at transistor is 100 if the value of the emitter current is 10mA, then determine the value of the conductor and base current
Ie=10mA,β=100I_e=10mA , \beta=100Ie=10mA,β=100
Base current Ib=Ieβ+1=10100+1=10101=0.099mAI_b=\dfrac{I_e}{\beta+1}=\dfrac{10}{100+1}=\dfrac{10}{101}=0.099mAIb=β+1Ie=100+110=10110=0.099mA
Conductor current Ic=βIb=100×0.099=9.9mAI_c=\beta I_b=100\times 0.099=9.9mAIc=βIb=100×0.099=9.9mA
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