A 6.82 kg bowling ball moves at 4.29 m/s. How fast must a 2.36 g Ping-Pong ball move so that the two balls have the same kinetic
energy?
Answer in units of m/s
1
Expert's answer
2012-11-29T08:00:38-0500
The kinetic energy is K=(mV^2)/2 Let x m/s is the velocity of Ping- Pong ball. If the kinetic energies are the same then: 6.82*(4.29)^2/2=0.00236*x^2/2 x^2=6.82*(4.29)^2/0.00236=53184.7 x=230.6 m/s
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