For a DC brush motor, if supply voltage = 200 V, Armature current = 10 Amp, and Armature resistance = 0.5 ohms, then the Eb will be …….
Supply voltage, V=200 VV=200\space VV=200 V
Armature current, IA=10 AI_A=10\space AIA=10 A
Armature Resistance, RA=0.5 ΩR_A=0.5\space\OmegaRA=0.5 Ω
Eb=VT+IARAE_b=V_T+I_AR_AEb=VT+IARA
Eb=200+(10×0.5)E_b=200+(10\times0.5)Eb=200+(10×0.5)
Eb=205 VE_b=205\space VEb=205 V
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