What is the circuit (amps) for a parallel circuit containing a 12 V potential and three resistors R1= 3 ohms, R2=2 ohms, and R3= 1 ohm?
Net resistance-
1R=1R1+1R2+1R3\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}R1=R11+R21+R31
=13+12+11=2+3+66=116=\dfrac{1}{3}+\dfrac{1}{2}+\dfrac{1}{1} \\[9pt] =\dfrac{2+3+6}{6}\\[9pt] =\dfrac{11}{6}=31+21+11=62+3+6=611
So R=611ΩR=\dfrac{6}{11} \OmegaR=116Ω
Current in the circuit =VR=12611=22amps=\dfrac{V}{R}=\dfrac{12}{\frac{6}{11}}=22 amps=RV=11612=22amps
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