Answer to Question #189317 in Electric Circuits for Andrei

Question

   Two straight, parallel, current-carrying wires separated by a distance of 5cm contain the same 1000 A current, flowing in similar directions. Determine the force per unit length exerted by the two wires.

Answer 1

Given:

2 straight current carrying wire

i=1000 A (in both)

direction= same ( therefore attractive force)

distance b/w them (d) = 5 cm

for calculating we use EMF formula

as, magnetic force will be generated b/w both the wires.

$\boxed {F={\mu_o( i_1 )(i_2 \over2\pi d}}$

but, here i₁=i₂

therefore,

$\boxed {F={\mu_o i^2 \over2\pi d}}$

after putting values we get,

$\boxed {F={(4 \pi \times 10^{-7})(1000)^2\over 2\pi (5 \times10^{-2})}}$

$\boxed {F=4 Nm^{-1}}$