Question #186695

Find the Vrms across each of the three elements when a 10 ohms resistor, 10mH inductor and 10nF capacitor are connected in series with a 10MHz voltage source. The rms current through the circuit is 0.50A.


1
Expert's answer
2021-04-29T10:42:23-0400

The total impedance in the series RLC circuit is

Z=R2+(ωL1ωC)2=100+(1071021107108)2=100+(10510)2=105  Ω\displaystyle Z = \sqrt{R^2 + (\omega L -\frac{1}{\omega C})^2} = \sqrt{100 + (10^7 \cdot10 ^{-2} -\frac{1}{10^{7} \cdot 10^{-8}})^2} = \sqrt{100+ (10^5-10)^2} = 10^5\; \Omega

Then

Vrms=IrmsZ=0.5A105Ω=5106  V=5  μV\displaystyle V_{rms} = \frac{I_{rms}}{Z} = \frac{0.5 A}{10^5 \Omega} = 5 \cdot 10^{-6} \; V = 5 \; \mu V


Answer: 5  μV5 \; \mu V


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Comments

TOPE MONSURAT OYEYEMI
30.04.21, 09:02

Thanks you for the well explained solution to my question.

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