A 0.20 kg stone is held 1.3m above the top edge of a water well and then dropped into it. The well has a depth of 5.0m. Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone-Earth system (a) before the stone is released and (b) when it reaches the bottom of the well? (c) What is the change in gravational potential energy of the system from release to reaching the bottom of the well?
1
Expert's answer
2012-11-14T07:01:07-0500
Before3: mgh, as from formula. mgh=0.2*1.3*9.8=2.548 after: mgh=-0.2*9.8*5=-9.8 Change: 2.548+9.8=12.28
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Dear visitor, please use panel for submitting new questions
: A force F = (30i – 40j) N is applied on an object, the object travels a displacement S = (-9i-3j) m. Find the work done by the force on the object.
Leave a comment