Calculate the energy stored in the capacitor network in the figure below when the capacitors are fully charged and when the capacitances are C1-12 0µF C2=2.0μF, and C3=4 0µF, respectively.
VT=12.0 V
Let us find voltage through each capacitor.
C2 and C3 are in parallel, so voltage across C2 and C3 will be the same.
C1 = 12 µF
C2 + C3 = 6 µF
"V_1 = 12 \\times \\frac{6}{6+12} = 4 \\;V"
V2 = V3 = 12 – 4 = 8 V
Energy "= \\frac{1}{2}CV^2"
"U_1 = \\frac{1}{2}(12)(4)^2 = 96 \\;\u00b5J \\\\\n\nU_2 = \\frac{1}{2}(2)(8)^2 = 64 \\;\u00b5J \\\\\n\nU_3 = \\frac{1}{2}(4)(8)^2 = 128 \\;\u00b5J"
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