Question #184154

Two 80-0 resistors are connected in series with 0.15 A flowing through them?

Find a. Total Resistance (Rt)

b. Voltage drop (Vt) across resistors

c. Current through the circuit



1
Expert's answer
2021-04-26T09:49:03-0400

To be given in question

R1=R2 =80 ohm=80\ ohm

I=0.15ampI=0.15amp

To be asked in question

(a)total resistance

Rt=?

(b) voltage drop (v)=?

(c) current through the circuit=?

We know that


(a) series combination

Rt=R1+R2R_{t}=R_{1}+R_{2}

put value

Rt=160 ohm

(b) voltage drope

V1=IR1V_{1} =IR_{1}

V1=0.15×80=12VoltV_{1}=0.15\times80=12Volt

V2=IR2V_{2}=IR_{2}

V2=0.15×80=12VoltV_{2}=0.15\times80=12 Volt

V=V1+V2V=V_{1}+V_{2}

V=12+12=24VoltV=12+12=24Volt

(c) current through the circuit

I=VRI=\frac{V}{R}

I=24160=0.15ampI=\frac{24}{160} =0.15 amp


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