A 1.5 volt battery is connected to a 10 ohm resistor.
a. What current passes through the resistor?
b. What is the power developed by this resistor?
a.CurrentI=VoltageVResistanceRa. Current I =\frac {Voltage V} {Resistance R}a.CurrentI=ResistanceRVoltageV
I=1.510=0.15AI= \frac{1.5} {10} = 0.15AI=101.5=0.15A
b. PowerP=VIPower P = VIPowerP=VI
P=1.5×0.15=0.225WP= 1.5\times 0.15= 0.225 WP=1.5×0.15=0.225W
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