Answer to Question #182544 in Electric Circuits for farouk

Question

q1 = 3.1 uc ,q2=11.4 uc ,q3= - 2.8 uc , d1= 4.9 cm ,

 d2=8.1 cm ,the net electric force on q1

Answer 1

To be given in question

q₁=3.1$\mu$ $C$

q₂=11.4$\mu$ $C$

q₃=-2.8$\mu$ $C$

d₂=4.9 cm =$4.9\times10^{-2} meter$

d₂=8.1 cm=8.1$\times10^{-2} meter$

To be asked in question

$(F_{net}){q_{1}}=?$

We know that

Electric force between charge q₁and q₂

$F_{12} =k\frac{q_{1}q_{2}}{r_{12}^2}$

Put values

$F_{12}=\frac{9\times10^9\times3.1\times10^{-6}\times11.4\times10^{-6}}{{.049}^2}$

$F_{12}=132.46N$

Electric force between charge q₁and q₃

$F_{13}=\frac{ kq_{1}q_{3}}{r_{13}}$

Put value

$F_{13}=-\frac{9\times10^9\times3.1\times10^{-6}\times2.8\times10^{-6}}{{.081}^2}$

$F_{13}= -11.9067N$

Net force

$F=F_{12}+F_{13}$

$F_{net}=132.46-11.9067$

$F_{net}=120.55 N$