Question #182207

a series circuit with R=10 ohms,L=100mH and C=100microF is supplied with 200 V/50Hz. Find the impedance,current,power,power factor.


1
Expert's answer
2021-04-23T07:25:40-0400

Impedance

XL=2πfL=2π×50×100×103=20πX_L=2\pi fL=2\pi \times 50 \times 100 \times 10^{-3}=20\pi

XC=12πfL=12π×50×100×103=120πX_C=\frac{1}{2\pi fL}=\frac{1}{2\pi \times 50 \times 100 \times 10^{-3}}=\frac{1}{20\pi}

Z=102+(20π120π)2=63.6ΩZ=\sqrt{10^2+(20\pi- \frac{1}{20\pi}})^2=63.6 \Omega

Current

I=VZ=20063.6=3.145AI=\frac{V}{Z}= \frac{200}{63.6}=3.145 A

Power

P=IV=3.145×200=628.93WP=IV=3.145 \times 200=628.93 W

Power factor

cosϕ=RZ=1063.6=0.157cos \phi =\frac{R}{Z}=\frac{10}{63.6}=0.157


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