a series circuit with R=10 ohms,L=100mH and C=100microF is supplied with 200 V/50Hz. Find the impedance,current,power,power factor.
Impedance
XL=2πfL=2π×50×100×10−3=20πX_L=2\pi fL=2\pi \times 50 \times 100 \times 10^{-3}=20\piXL=2πfL=2π×50×100×10−3=20π
XC=12πfL=12π×50×100×10−3=120πX_C=\frac{1}{2\pi fL}=\frac{1}{2\pi \times 50 \times 100 \times 10^{-3}}=\frac{1}{20\pi}XC=2πfL1=2π×50×100×10−31=20π1
Z=102+(20π−120π)2=63.6ΩZ=\sqrt{10^2+(20\pi- \frac{1}{20\pi}})^2=63.6 \OmegaZ=102+(20π−20π1)2=63.6Ω
Current
I=VZ=20063.6=3.145AI=\frac{V}{Z}= \frac{200}{63.6}=3.145 AI=ZV=63.6200=3.145A
Power
P=IV=3.145×200=628.93WP=IV=3.145 \times 200=628.93 WP=IV=3.145×200=628.93W
Power factor
cosϕ=RZ=1063.6=0.157cos \phi =\frac{R}{Z}=\frac{10}{63.6}=0.157cosϕ=ZR=63.610=0.157
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments