Answer to Question #180463 in Electric Circuits for Ivanah Mae G. Aclo

Question

The capacitors have values C1= 2.0 uf and C2= 4.0 uF, C3=5.0 uF C4= 7.0 uF and the potential difference across the battery is 9.0 V. Assume that the capacitors are connected in series?

Answer 1

Total capacitance for capacitors in series is C_T

$Q=CV$

Were C is Capacitance

V is Voltage supplied

Q IS Charged across the capacitors

$Q_{T}= \frac{1}{c_{1}}+ \frac{1}{c_{2}}+ \frac{1}{c_{3}}+\frac{1}{c_{4}}$

C_T= $\frac {1}{2} + \frac {1}{4} + \frac{1}5 + \frac{1}{7} = 0.915uf$

Q= $\ 0.915× 9 = 8.235$

Q= 8.235uC