Question

An electrician experienced a mild shock when he accidentally touched a live wire carrying 1.5 amperes of current within a duration of 1.3 seconds. How many electrons constitute the given current that went through the body of the electrician?

Answer 1

Given

I = 1.5 Amp

t = 1.3 seconds

Solution:

as we know that,

Q= charge flows through a wire in given time.

$\boxed{Q=It}$

​ $\therefore$ $Q=1.95\space C$ ......................(1)

and from defini tion of charge we know that

Q=total no. of electrons *charge on a electron

i.e,

$\boxed{Q=ne}$

value of $e=1.6\times 10^{-19} C$C

value Q from (1) , Q = 1.95 C

$\implies$

$\boxed { n={Q\over e}}$

$\bigstar$ Answer - no. of electron

$\boxed{ n = 1.21875\times10^{19}}$