Question #172694

A straight conductor with length 10.0 m passes through a uniform magnetic field 0.75 m wide. The current in the conductor is 2.0 A directed east, and the magnetic field is 0.60 T [down]. Find the magnetic force on the conductor, including direction.


1
Expert's answer
2021-03-21T11:36:37-0400
FB=BILsinθ=0.6 T2.0 A10.0 msin90=12 N.F_B=BILsin\theta=0.6\ T\cdot2.0\ A\cdot10.0\ m\cdot sin90^{\circ}=12\ N.

According to the right-hand rule, the magnetic force directed upward.


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