2.7 Find the power dissipated in the following resistors
1) P1=I12R1=102⋅100000=10⋅106 (J)=10 MJP_1=I_1^2R_1=10^2\cdot100000=10\cdot10^6\ (J)=10\ MJP1=I12R1=102⋅100000=10⋅106 (J)=10 MJ
2) P2=I22R2=0.0252⋅45=0.028 (J)P_2=I_2^2R_2=0.025^2\cdot45=0.028\ (J)P2=I22R2=0.0252⋅45=0.028 (J)
3) P3=I32R3=0.0752⋅1000=5.625 (J)P_3=I_3^2R_3=0.075^2\cdot1000=5.625\ (J)P3=I32R3=0.0752⋅1000=5.625 (J)
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