Question #17134
Two parallel current carrying conductors exert some force on each other. If the current in both conductors is doubled the force becomes k times. Find the value of k.
Expert's answer
According to the Ampere's force law the force of interaction between two parallel current carrying conductors is
F1 = 2μI²/(4πr)
before doubling and
F2 = 2μ(2I)²/(4πr)
after doubling. Therefore, the coefficient k is
k = F2/F1 = 2μ(2I)²/(4πr) / (2μI²/(4πr)) = (2I)²/(I²) = 4.
F1 = 2μI²/(4πr)
before doubling and
F2 = 2μ(2I)²/(4πr)
after doubling. Therefore, the coefficient k is
k = F2/F1 = 2μ(2I)²/(4πr) / (2μI²/(4πr)) = (2I)²/(I²) = 4.
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