Question #170570

An object 6cm high is placed 30cm in front of a convex mirror of focal length 15cm. Find the image position and determine it's height


Expert's answer

Height of object(h)=6 cm(h)=6\space cm

Focal length of mirror(f)=+15 cm(f)=+15\space cm

Distance of the object from mirror(u)=−30 cm(u)=-30\space cm

Using mirror formula:

1u+1v=1f⇒1v=115−1(−30)\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}\\\Rightarrow\dfrac{1}{v}=\dfrac{1}{15}-\dfrac{1}{(-30)}

⇒v=10 cm\Rightarrow v=10\space cm

Height of image(h′)=10(−30)×6=−2 cm(h')=\dfrac{10}{(-30)}\times6=-2\space cm

Negative sign indicates that the image formed is inverted


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