Assume you need a 5.0 ohms resistor and you have available #22 guage wire with a diameter of 6.38 ×10^-4 m.compute the length of wire needed for the resistor.
The resistance is:
"R=\\rho\\frac{l}{A}=\\rho\\frac{4l}{\\pi d^2},"
where "\\rho" - the resistivity of a material (for copper "\\rho=1.724\\cdot10^{-8}\\space Ohm\\cdot m" );
l - the length of wire;
A - the cross-sectional area of wire;
d - the diameter of wire;
"l=\\frac{\\pi d^2R}{4\\rho}=\\frac{3.14\\cdot (6.38\\cdot 10^{-4})^2\\cdot5}{4\\cdot1.724\\cdot 10^{-8}}=92.7\\space m."
Answer: 92.7 m.
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