Question #169354

It takes a proton 71 seconds to cross a potential difference of 101000V what is the average power expended by the electric field



1
Expert's answer
2021-03-08T08:24:13-0500

Answer

the average power expended by the electric field is given by

P=Vi=Vqt=101000×1.6×101971=2.276×1016WattsP=Vi=\frac{Vq}{t}\\=\frac{ 101000\times1.6\times10^{-19} }{71} \\=2.276\times10^{-16}Watts


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