It takes a proton 71 seconds to cross a potential difference of 101000V what is the average power expended by the electric field
Answer
the average power expended by the electric field is given by
P=Vi=Vqt=101000×1.6×10−1971=2.276×10−16WattsP=Vi=\frac{Vq}{t}\\=\frac{ 101000\times1.6\times10^{-19} }{71} \\=2.276\times10^{-16}WattsP=Vi=tVq=71101000×1.6×10−19=2.276×10−16Watts
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