Answer to Question #167626 in Electric Circuits for edlen kate

Question

A 7.0 * 10^-9 C point charges at the center of a 5.0 cm radius sphear. What is the electric flux through the sphere surface?

Answer 1

Electric field of sphere = $\dfrac{Q}{4\pi\epsilon_{\omicron}R^2}$

Surface area of sphere = $4\pi R^2$

Flux $=$ $E\times area$

$\space\space\space\space\space\space\space=\dfrac{Q}{4\pi\epsilon_{\omicron}R^2}\times4\pi R^2$

$\space\space\space\space\space\space\space=\dfrac{Q}{\epsilon_{\omicron}}$

$\space\space\space\space\space\space\space=\dfrac{7\times10^{-9}}{8.8\times10^{-12}}=7.95\times10^2\space Nm^2/C$