Consider a voltage amplifier having a frequency response of the low-
pass STC type with a dc gain of 60 dB and a 3-dB frequency of 1000
Hz. Find the gain in dB at f = 10 Hz
First, we will use the
low pass Magnitude response equation.
AVdB=20∗log10(AV)A_{VdB} = 20*log_{10}(A_V)AVdB=20∗log10(AV)
60=20∗log10(AV)60 = 20*log_{10}(A_{V})60=20∗log10(AV)
3=log10(AV)→AV=103=10003 = log_{10}(A_V) \to A_V = 10^3 = 10003=log10(AV)→AV=103=1000
Next, knowing that ffo=ωωo\large\frac{f}{f_o} = \frac{\omega}{\omega_o}fof=ωoω, and that fof_ofo is given we can plug that in formula:
AV(f)=10001+(f1000)2=A_V(f) = \frac{1000}{\sqrt{1+(\frac{f}{1000})^2}} =AV(f)=1+(1000f)21000= 995.95995.95995.95
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