Question

 A small positively-charged particle that has a charge of 1.20x10^-4 C came into the vicinity of a large positively-charged particle that created an electric force upon the test charge with an amount of 23.0x10 N. What is the Electric Field Strength exerted by the point charge then?

Answer 1

charge - $q = 1.2*10^{-4}C$ Force - $F = 230N$

The Filed Strength exerted by the point is $E = \large\frac{F}{q}= \frac{230N}{1.2*10^{-4}C}$ $= 19.1(6)*10^{5}\large\frac{N}{C}$