Question #16520

A 3 kg cart starting from rest on a frictionless surface is pulled by a horizontal mass-less rope with a constant force of 6 N. What is the acceleration of the cart, and how fast is it moving at the end of two seconds?

Expert's answer

We know that F=maF = ma. So, we can find acceleration: F=maa=Fm=6N3kg=2ms2F = ma \Rightarrow a = \frac{F}{m} = \frac{6N}{3kg} = 2\frac{m}{s^2}.

And we know that a cart starting from rest, so, the velocity in the beginning of the motion is equal to the zero: v0=0v_0 = 0. And we know acceleration. So, we can find the velocity after 2 seconds of the motion:


v2=v0+at=0+22=4ms.v_2 = v_0 + a \cdot t = 0 + 2 \cdot 2 = 4 \frac{\mathrm{m}}{\mathrm{s}}.


Answer: acceleration is 2ms22\frac{\mathrm{m}}{\mathrm{s}^2}; velocity at the end of two seconds is 4ms4\frac{\mathrm{m}}{\mathrm{s}}.

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