How many electrons pass through a conductor in 3 milliseconds if the current is 5 mA
Charge passed through a conductor:
q=It=5⋅10−6⋅3⋅10−3=1.5⋅10−10Cq=It=5\cdot10^{-6}\cdot3\cdot10^{-3}=1.5\cdot10^{-10}Cq=It=5⋅10−6⋅3⋅10−3=1.5⋅10−10C
E:lementary charge:
e=1.6⋅10−19Ce=1.6\cdot10^{-19}Ce=1.6⋅10−19C
Number of electrons pass through a conductor:
n=q/e=1.5⋅10−101.6⋅10−19=9.375⋅108n=q/e=\frac{1.5\cdot10^{-10}}{1.6\cdot10^{-19}}=9.375\cdot10^{8}n=q/e=1.6⋅10−191.5⋅10−10=9.375⋅108
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