Question #162776

How many electrons pass through a conductor in 3 milliseconds if the current is 5 mA


Expert's answer

Charge passed through a conductor:

q=It=51063103=1.51010Cq=It=5\cdot10^{-6}\cdot3\cdot10^{-3}=1.5\cdot10^{-10}C

E:lementary charge:

e=1.61019Ce=1.6\cdot10^{-19}C

Number of electrons pass through a conductor:

n=q/e=1.510101.61019=9.375108n=q/e=\frac{1.5\cdot10^{-10}}{1.6\cdot10^{-19}}=9.375\cdot10^{8}


LATEST TUTORIALS
APPROVED BY CLIENTS