Answer to Question #162168 in Electric Circuits for Sarah

Question #162168

A silver wire has a resistance of 40 ohms at 19 degrees Celsius. After several hours of heating, the resistance of the coil has increased to 60 ohms. What is the new temperature of the wire?


1
Expert's answer
2021-02-08T18:37:06-0500

The electrical resistance of a conductor at temperature TT :

RT=Rr(1+α(TTr))R_T=R_r(1+\alpha(T-T_r))

where RrR_r is resistance of conductor at reference temperature TrT_r ,

α\alpha is temperature coefficient of resistance at reference temperature TrT_r

α=0.003819\alpha=0.003819 for silver at Tr=20°CT_r=20\degree C

Then:

Rr=R191+α(1920)R_r=\frac{R_{19}}{1+\alpha(19-20)}

Rr=401+0.003819(1920)=40.15R_r=\frac{40}{1+0.003819\cdot(19-20)}=40.15 ohms


The new temperature of the wire:

T=(RT/Rr1)/α+TrT=(R_T/R_r-1)/\alpha+T_r

T=(60/40.151)/0.003819+20=149.46°CT=(60/40.15-1)/0.003819+20=149.46\degree C


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