A wire carries a steady current of 2.40 A. A straight section of the wire is 0.750 m long and lies along the x-axis within a uniform magnetic field, If the current is in the x-direction, what is the magnetic force on the section of wire?
Answer
The magnetic field on the segment of wire
"F=IL\\times B"
Using current I=2.4A
Length L=0.750m
So using above equation magnetic field is found
B=1.6T
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