(a)
Ceq=C1+C2,Ceq=5.0⋅10−6 F+12⋅10−6 F=17⋅10−6 F=17 μF.(b) The potential difference across each element in the parallel circuit is the same, therefoore:
ΔV1=ΔV2=ΔV=9.0 V.(c)
Q1=C1ΔV=5.0⋅10−6 F⋅9.0 V=45⋅10−6 C=45 μC,Q2=C2ΔV=12.0⋅10−6 F⋅9.0 V=108⋅10−6 C=108 μC.
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