Question #15709

The brochure advertising a sports car states that the car can be moving at 100.0 km/h, and stop in 37.19 meters. What is its average acceleration during a stop from that velocity? Express your answer in m/s2. Consider the car's initial velocity to be a positive quantity.

Expert's answer

The brochure advertising a sports car states that the car can be moving at 100.0 km/h, and stop in 37.19 meters. What is its average acceleration during a stop from that velocity? Express your answer in m/s². Consider the car's initial velocity to be a positive quantity.

Solution:

Let:


v=100km/h=27.78m/sv = 100 \, \text{km/h} = 27.78 \, \text{m/s}S=37.19mS = 37.19 \, \text{m}


a–?


v=at,S=12at2t=2sav = at, \, S = \frac{1}{2} at^2 \Rightarrow t = \sqrt{\frac{2s}{a}}v=2asv = \sqrt{2as}a=v22sa = \frac{v^2}{2s}a=27.782237.19=10.38m/s2a = \frac{27.78^2}{2 \cdot 37.19} = 10.38 \, \text{m/s}^2


Answer: 10.38 m/s²

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