Answer to Question #155755 in Electric Circuits for Tadiwa Taaziva

Question

An arc with radius R=0.25m and length  l=π/12 meter carries 3A current. What is the magnetic field B at the center of the arc.

Answer 1

Magnetic field of any arc:

$B = \frac{μ_0}{4π} \times \frac{I}{R} \times α \\ α = \frac{AB}{R} \\ B = \frac{μ_0}{4π} \times \frac{3}{0.25} \times \frac{π}{3} = μ_0 \;Tesla$

Answer: μ₀