a circuit in which a capacitor of capacitance 4700microfarad is to be connected across a potential difference of 9v.He has 4700microfarad 6v capacitor available. draw the diagram to show how the 4 capacitor could be used for this purpose
Given physical quantities
= 4700 mkF
= 9v
= 4700 mkF
= 6v
4700 mkF * 9v + 4700 mkF * 6v = 4700 mkF * 15v
15v
first diagramm
The next diagram for this purpose
= 1175 mkF
C = 17625 mkC
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