A solenoid of length 2.2 m has a diameter of 0.9 m. The magnetic field at its centre is 0.4 tesla. Estimate the energy stored in the field of this coil.
The energy stored in the solenoid is
U=B2Al2μ0U=\frac{B^2 Al}{2 \mu_0}U=2μ0B2Al
=B2πr2l2μ0=\frac{B^2 \pi r^2l}{2 \mu_0}=2μ0B2πr2l =(0.4)2π(0.45)2(2.2)2(4π×10−7)=\frac{(0.4)^2 \pi (0.45)^2(2.2)}{2 (4 \pi \times10^{-7})}=2(4π×10−7)(0.4)2π(0.45)2(2.2) =2.23×105J=2.23 \times 10^5 J=2.23×105J
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