Find the equivalent capacitance.
C1=6.0 µF, C=4.0 µF
Answer
When these two capacitance connected in parallel then equivalent capacitance is given
C=C′+C′′=6+4=10μFC=C'+C''=6+4=10\mu FC=C′+C′′=6+4=10μF
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments