Question

A simple circuit is constructed in which a 1 Ω resistor is connected across a 1 V battery and so draws a 1 A current. What is the current drawn from the battery if:

(a) an extra 1 Ω resistor is connected in series with the existing one?

(b) four extra 1 Ω resistors are connected in series with the existing one?

Answer 1

1. $I=\frac{U}{R}=\frac{1}{1+1}=0.5A$
2. $I=\frac{U}{R}=\frac{1}{5\times1}=0.2A$