Answer to Question #150276 in Electric Circuits for Khan Asf

Question

There are n equal resistors. Series connection of these resistors gives 98 Ohms. Parallel connection of these resistors gives 2 Ohms. Find n.

Answer 1

Solution:

R*n = 98

$\dfrac{R}{n} =2$ R/n = 2 

2n*n = 98

n = $\sqrt{\smash[b]{ \tfrac{98}{2} }}$ = 7 

R = 14 ohm 

check : 

14*7 = 70+28 = 98 ohm

$\tfrac{14}{7}=2 ohm$

Answer:

n=2