Answer to Question #144327 in Electric Circuits for moh

Question

The total electric flux through a closed cylindrical (length = 1.2 m, diameter = 0.20 m) surface is
equal to 5.0 N  m2
/C. Determine the net charge within the cylinder

Answer 1

From the Gauss’ law the net electric flux of a closed object is

$Φ = \frac{q}{ε_0}$

q is the charge within the cylinder

ε₀ is permittivity in free space

$q = Φ \times ε_0$

$q = (-5.0\; N\;m^2/C)(8.55 \times 10^{-12}\;C^2/Nm^2)$

$q = -44.25 \times 10^{-12}\;C = -44 \;pC$