The resistance of serial resistors is:
"R = R_1 + R_2 = 50\\Omega +8\\Omega = 58\\Omega" The resistance of parallel resistors is:
"R = \\dfrac{R_1R_2}{R_1+R_2} = \\dfrac{50\\Omega\\times 8\\Omega}{50\\Omega+8\\Omega}\\approx 6.9\\Omega" Answer. In series: 58 ohms, parallel: 6.9 ohms.
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