Question #14313

10. A hockey slap-shot is hit at the goal, 30 meters away. The puck, which weighs 0.250 kg, covers that distance in 0.38 seconds. How much momentum does the puck have?

Expert's answer

Question #14313

Given that the puck covered 30 meters in 0.38 seconds, find the velocity v=30m0.38s75.95m/sv = \frac{30m}{0.38s} \approx 75.95 \, \text{m/s}.

The momentum (linear momentum) is given by p=mvp = m v, hence p=75.95m/s0.25kg19.74kgm/sp = 75.95 \, \text{m/s} \cdot 0.25 \, \text{kg} \approx 19.74 \, \text{kg} \cdot \text{m/s}.

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